Question
Three numbers are in ratio 3:4:7. If the sum of the
squares of those three numbers is 666 then find the sum of the three numbers.Solution
A : B : C = 3x : 4x : 7x A2Â + B2Â + C2Â = 9x2Â + 16x2Â + 49x2Â = 74x2 => 74x2Â = 666 => x = 3 => A + B + C = 3x + 4x + 7x = 14x = 14 ĂÂ 3 = 42
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