Question
B1 is a point on the side AC of ∆ ABC and B1B is joined. line is drawn through A parallel to B1B meeting BC at A1 and another line is drawn through C parallel to B1B meeting AB produced at C1. Then
∆AA1C & ∆BB1C AA1 ‖ BB1 (BB1) / (AA1) = (B1C) / (AC) By ratio of Similarity in ∆ACC1 ~ ∆ABB1 = BB1 ‖ CC1 = (BB1) / (CC1) = (AB1) / (AC) = (BB1) / (CC1) = (AC – B1C) / (AC) = (BB1) / (CC1) = 1 – ((B1C) / (AC) from (1) (BB1) / (CC1) = 1 – (BB1) / (AA1) BB1[1/CC1 + 1 / AA1] = 1 = (1 / CC1) + (1 / AA1) = (1 / BB1)More Geometry Questions
- Question 1
- In Fig. if QT ⊥ PR, ∠ TQR = 40 ° and ∠ SPR = 30 ° , find x and y.
- If the area of ∆ ABC is 33 cm2 & G is the centroid of ∆ ABC.then the area of the ∆ BGC?
- If O is circumcentre of acute angled triangle ABC, if ∠ BOC = 60˚ then ∠ BAC = ?
- ABCD is cyclic quadrilateral in which A = 72º and B = 105º What is the difference between the measures of C and D?
- The lengths of three medians in a triangles are 15 cm, 20 cm, 25 cm. What is the area of that traingle (in cm 2 )?
- Find the difference between angle and its complement if the angle is four-fifth of its complement.
- What is the sum of the smallest and the largest angles of the triangle?
- The length of the each side of an equilateral triangle is 42√3 cm . The area of circumcircle, (cm 2 ) is
- If O is the orthocentre of ΔABC , if ∠ BOC = 1350 then what is the measure of ∠ BAC?
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
