If the number of balls faced by Cheteshwar Pujara to take 1’s is greater than that for 2’s, then he can score a maximum of how many runs?
Runs by 4’s = 4 × 4 = 16 ……………(i)
Number of dot balls = 12
So remaining balls = 41 – (4 + 12) = 25
So, to maximize his score in 25 balls, he can take 13 one’s and 12 two’s. …….…(ii)
So a maximum of 16 + 13 × 1 + 12 × 2 = 53 runs
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