Distance between destinations I and V = 468 + 376 + 324 + 372 = 1540 km If both cars meet after ‘t’ hours, then 96t + 124t = 1540 220t = 1540 t = 7 hours Hence, both cars will meet at 10 am.
(15.98% of 399.99) - 6.998 = √?
26.23 × 31.82 + 44.8% of 1200 + ? = 1520
?2 = 159.97% of 65.004 + 319.98 ÷ 15.99 - 24
41.78% of 1499 + (9/13) × 389.84 = ?% of 1599.67 + 180.45
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
(88.931% of 435) + (61.521% of 516) = ?
119.98% of 80.02 - 15.12 × 2.02 + 19.95 = ?
(14.98% of 279.99) - 8.998 = √?
(33.95)2 – (25.004)2 + (18.0099)2 – (9.07)2 = ? - (14.990)2
60.22 of 349.98% + 419.99 ÷ 14.18 = ?