Question
By what percent is the distance between the destination
II and V is less than that between the destination IV and VII? In the following table eight destinations - I, II, III, IV, V, VI, VII and VIII - have been given. A car crosses all the destinations if it starts from destination I to destination VIII. Question mark (?) in the table show the missing figures. Study the table carefully and answer the following given questions.Solution
Distance between destinations II and V = (376 + 324 + 372) km = 1072 km Distance between destinations IV and VII = 372 + 308 + 424 = 1104 km Required percentage = `(1104-1072)/1104` `xx` 100 = 2.89%=3%
2470.03 ÷ 64.98 x 39.9 = ? + 20.32
27.27% of 5501.22 + 12.53% of 158.99 – √ 1599 = ?
35.11% of 159.99 + √195.97 ÷ 7.02 = ?
(1011 × 4.465 + 1012 × 0.3535) ÷ (160 × 10⁵) = 10? ÷ 2
...( 1000)1/3 × 10.11 × 4.97 ÷ 10.32 =? – 15.022
(2520.33 ÷ 41.67) × (√168.88 + √80.78) - 10% of 1499.85 = ?
25.22% of (59.9 × 8.01) + 69.97 =?
25.22 of 359.98% + 499.99 ÷ 25.18 = ?
(29.892 × √290) + 32.98 × 6.91 = ?