Question
In city S, if number of candidates who were not appeared
is 2/11 of the total number of applicants, then find the approximate percentage of the candidates who got selected out of appeared?Solution
Let the total number of applicants be x Total number of non-appeared candidate = 2/11 of x Total number of appeared candidates = Number of applicants – Number of non-appeared candidates x – 2/11 of x = 9x/11 Total number of applicants who got selected =60% of x = 3x/5 So required % = [(3x/5)/(9x/11)] × 100 = 3300/45 = 73.33% = Approx. 73%
More Di With Missing Numbers Questions
2470.03 ÷ 64.98 x 39.9 = ? + 20.32
27.27% of 5501.22 + 12.53% of 158.99 – √ 1599 = ?
35.11% of 159.99 + √195.97 ÷ 7.02 = ?
(1011 × 4.465 + 1012 × 0.3535) ÷ (160 × 10⁵) = 10? ÷ 2
...( 1000)1/3 × 10.11 × 4.97 ÷ 10.32 =? – 15.022
(2520.33 ÷ 41.67) × (√168.88 + √80.78) - 10% of 1499.85 = ?
25.22% of (59.9 × 8.01) + 69.97 =?
25.22 of 359.98% + 499.99 ÷ 25.18 = ?
(29.892 × √290) + 32.98 × 6.91 = ?
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