Question
A boat covers a distance of 57 km upstream in 9.5
hours. If the boat's speed in still water had been doubled, it would have taken only 2 hours to cover 60 km upstream. What is the speed of the current?Solution
Let the speed of the boat in still water and the speed of the current be ‘x’ km/hr and ‘y’ km/hr, respectively According to the question, (x – y) = 57/9.5 = 6….. (1) And, 2x – y = 60/2 = 30…. (2) On solving equation (1) and (2), we get Speed of the current = y = 18 km/hr
`sqrt(1297)` + 189.99 =?
90.004% of 9500 + 362 = ?
(74.76 ÷ 12.11 X ?)% of 239.89 = 600.19
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3
If tan θ + cot θ = 16, then find the value of tan2θ + cot2θ.
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
(95.89% of 625.15 + 36.36% of 499.89) ÷ 6.02 = ? – 269.72
11.89 × 2.10 × 4.98 × 4.03 ÷ 7.98 of 15.03 = ?