Question
The average salary of department A with n employees is
₹40,000, and that of department B with (n+15) employees is ₹50,000. If the combined average salary of all employees is ₹46,000, find the value of ‘n+10’.Solution
ATQ, Total salary of department A = n × 40,000 = 40,000n Total salary of department B = (n+15) × 50,000 = 50,000n + 750,000 (40,000n + 50,000n + 750,000) / (2n + 15) = 46,000 → 90,000n + 750,000 = 92,000n + 690,000 → 2,000n = 60,000 → n = 30 Required answer = n + 10 = 40
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