Question
Three numbers are given such that when the average of any
two numbers is added to the third number, the resulting sums are 250, 240, and 230. Determine the difference between the largest and smallest numbers.Solution
ATQ;
Let the three numbers be x, y, and z.
So, 2x+y+z=250×2=500
x+2y+z=240×2=480
x+y+2z=230×2=460
Thus,
4×(x+y+z)=1440
x+y+z=360
Now,
x=500−360=140
y=480−360=120
z=460−360=100
Desired difference = 140−100=40
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