Question
Sum of ages of 90 players is 2250 years. The average age
of 30 of them is 20 years and average age of another 30 of them is 15 years. Find the average age of the remaining players.Solution
Given, sum of age of 90 players = 2250 years
Sum of age of 30 players = 30 × 20 = 600 years
Sum of age of another 30 players = 30 × 15 = 450 years
Remaining number of players = 90 – 30 – 30 = 30
Average age of remaining 30 players = {(2250 – 600 – 450)/30} = (1200/30) = 40 years
20 25 54 165 662 ?
...21Â Â Â Â Â Â Â Â Â Â 48Â Â Â Â Â Â Â Â Â Â 173Â Â Â Â Â Â Â Â 516Â Â Â Â Â Â Â Â 1245Â Â Â Â Â Â 2576Â Â Â Â Â Â ?
...Three series are provided below. You need to determine the values of A, B, and C and subsequently establish a relationship among them.
I: 4, 10...
1Â Â Â Â 1Â Â Â Â 8Â Â Â Â 4Â Â Â Â 27Â Â Â Â 9Â Â Â Â ?
...5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.5 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 20 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 113.5 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 799 Â ...
21 23 26 ? 39 51
...If 6 4 x 5.75 9,
Then, (x²-1) = ?
...4                14                  130                     512                �...
73920, 9240, ?, 220, 44, 11
3, 7, 16, 35, ?, 153
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