Question
The average of five consecutive
even numbers is 56, and the average of four consecutive odd numbers is 'n'. The ratio of the highest even number to the lowest odd number is 20:11. Determine the average of another set of five consecutive even numbers, where the lowest number of the new series is (n+2).Solution
ATQ, Let the consecutive even numbers are x, x+2, x+4, x+6, x+8 x+ x+2+ x+4+ x+6+ x+8 = 56×5 = 280 5x = 280-20 = 260 A = 52 Consecutive even numbers are 52, 54, 56, 58, 60 Highest even number = 60 Lowest odd number = 60/20×11 = 33 Consecutive odd numbers is 33, 35, 37, 39 Average of 4 consecutive odd numbers(n) = 144/4 = 36 Lowest number of the series = 36+2 = 38 Average of 5 consecutive another even numbers of series = 38+40+42+44+46 = 210/5 = 42
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