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      Question

      Consider the following stack operations. What will be

      the content of the stack after executing all the operations? Stack stack = new Stack ();Β  stack.push( 5 );Β  stack.push( 10 );Β  stack.pop();Β  stack.push( 15 );Β  stack.push( 20 );Β  stack.pop();Β  stack.push( 25 );Β 
      A [5, 10, 25] Correct Answer Incorrect Answer
      B [5, 15, 25] Correct Answer Incorrect Answer
      C [5, 10, 15] Correct Answer Incorrect Answer
      D [5, 15, 20] Correct Answer Incorrect Answer
      E [5, 25] Correct Answer Incorrect Answer

      Solution

      The stack operates on a Last-In, First-Out (LIFO) principle. The operations are executed as follows:

      1. stack.push(5) β†’ Stack: [5]
      2. stack.push(10) β†’ Stack: [5, 10]
      3. stack.pop() β†’ Removes the top element 10 . Stack: [5]
      4. stack.push(15) β†’ Stack: [5, 15]
      5. stack.push(20) β†’ Stack: [5, 15, 20]
      6. stack.pop() β†’ Removes the top element 20 . Stack: [5, 15]
      7. stack.push(25) β†’ Stack: [5, 15, 25]
      Thus, the final stack content is [5, 15, 25] . Why Other Options Are Wrong Option A: [5, 10, 25] This sequence assumes the second pop() operation does not occur. However, 20 is removed during the second pop() . Option C: [5, 10, 15] This sequence omits the addition of 25 in the final push() operation. Option D: [5, 15, 20] This sequence retains 20 in the stack, but 20 is removed during the second pop() . Option E: [5, 25] This sequence ignores the intermediate pushes of 15 and retains only 5 and 25 , which is incorrect.

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