Question
The average of two numbers βMβ and βNβ is 250
such that they are in the ratio 2:3 respectively. Another number βOβ is 120 more than βNβ and fourth number βPβ is 20% of the βMβ. Find the average of βOβ and βPβ.Solution
Sum of βMβ and βNβ = 250 Γ 2 = 500
Therefore,
βMβ = 500 Γ (2/5) = 200
βNβ = 500 β 200 = 300
βOβ = 300 + 120 = 420
βPβ = 0.2 Γ 200 = 40
Required average = {(420 + 40)/2} = 230
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