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    Question

    The batting average for 27 innings of a cricket player

    is 48 runs. His highest score in an innings exceeds his lowest score by 157 runs. If these two innings are excluded, the average score of the remaining 25 innings is 43 runs. Find his highest score in an innings.
    A 188 Correct Answer Incorrect Answer
    B 177 Correct Answer Incorrect Answer
    C 189 Correct Answer Incorrect Answer
    D 185 Correct Answer Incorrect Answer

    Solution

    Let the 25 innings score = x given -highest and lowest score difference = 157 H-L = 157---(1) total score of 25 innings - x/25=43 x =1075 Average score of 27 innings = 48 (x+ H+L)/27 = 48 put the value of x so, H + L = (48×27)-1075 = 1296-1075 H+L=221-----(2)  Eq (1) and (2)  2H = 157+221 =378 highest =H =189runs

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