Question
The batting average for 27 innings of a cricket player
is 48 runs. His highest score in an innings exceeds his lowest score by 157 runs. If these two innings are excluded, the average score of the remaining 25 innings is 43 runs. Find his highest score in an innings.Solution
Let the 25 innings score = x given -highest and lowest score difference = 157 H-L = 157---(1) total score of 25 innings - x/25=43 x =1075 Average score of 27 innings = 48 (x+ H+L)/27 = 48 put the value of x so, H + L = (48×27)-1075 = 1296-1075 H+L=221-----(2)  Eq (1) and (2) 2H = 157+221 =378 highest =H =189runs
√323.89 × (3.20) ÷ 9.02 = ?
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