Question
Average of 10 observations calculated by a student was
60 but when he again went through his observations he realised that he took value of three observations as 62, 54 and 50 in place of 86, 40 and 70 respectively and also realised that total observations taken by him was 9. Find the original average of all observations taken by him.Solution
Sum of 10 observations = 10 × 60 = 600 Original average = {600 + (86 + 40 + 70) - (62 + 54 + 50)}/9 = 630/9 = 70
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 4x² - 12x + 9 = 0
Equation 2: 2y² + 8y + 6 = 0
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