Question
What will be the 11th term of the arithmetic progression
3, 8, 13, _____?Solution
Tn = a + (n - 1)d Where a = first term, n = number of terms and d = difference In the given series a = 3, d = 8 – 3 = 5 Tn = 3 + (11 – 1) 5 Tn = 3 + 50 Tn = 53 Eleventh term = 53
18Â Â Â Â Â 45 Â Â Â Â Â 90 Â Â Â Â Â Â 235Â Â Â Â Â 450 Â Â Â Â Â 1125 Â Â Â Â Â 2250
...4178, 2153, 928, 303, 78, 55Â Â
24, 41, 58, 75, 94, 109
- In the given number series, find the wrong number.
81, 27, 9, 6, 1, 1/3, 1/9 Direction: Find the wrong number in given number series.
1102, 1140, 1186, 1240, 1318, 1412.
7, 16, 33, 74, 153, 312
Find the wrong number in the given number series.
12, 29, 68, 145, 322, 669
Find the Wrong number in the given number series.
137, 148, 190, 261, 361, 490Find the wrong term in the given series below.
2847, 2954, 2799, 3088, 2727, 3256
Find the wrong number in the given number series.
70, 94, 130, 182, 274, 406
Relevant for Exams:
