If 8 times the eighth term of an Arithmetic Progression (AP) is equal to 12 times its twelfth term, then the 20th term of the AP will be
Let the first term of the AP be a & the common difference = d 8th term = A8 = a + 7d 12th term = A12 = a + 11d According to question, 8 × (a + 7d) = 12 × (a + 11d) 8a + 56d = 12a + 132d 12a − 8a = 56d − 132d 4a = −76d a = −19d a + 19d = 0 = A20
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