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Let the first term of the AP be a & the common difference = d 8th term = A8 = a + 7d 12th term = A12 = a + 11d According to question, 8 × (a + 7d) = 12 × (a + 11d) 8a + 56d = 12a + 132d 12a − 8a = 56d − 132d 4a = −76d a = −19d a + 19d = 0 = A20
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