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      Question

      If (x + y) = 10 and xy = 21, then find the value of (x²

      + y²).
      A 62 Correct Answer Incorrect Answer
      B 58 Correct Answer Incorrect Answer
      C 48 Correct Answer Incorrect Answer
      D 54 Correct Answer Incorrect Answer

      Solution

      According to the question,
      (x + y)² = 10²
      ⇒ x² + y² + 2xy = 100
      ⇒ x² + y² + 2(21) = 100
      ⇒ x² + y² + 42 = 100
      ⇒ x² + y² = 100 – 42 = 58

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