Question
If sin 28° = 15/17 , then tan 62° =
?Solution
sin 28° = 15/17 = perpendicular/hypotenuse So perpendicular = 15 & hypotenuse = 17 so base = 8 But for angle 62° which is complimentary of 28°, perpendicular = 8 & base = 15. So tan 62° = perpendicular/base = 8/15 Alternate Method sin 28° = 15/17 or cos (90°-28°) = 15/17 or cos 62° = 15/17 -----(1) Squaring on both sides, we will get cos2 62° = 225/289 or (1 - sin2 62°) = 225/289 or sin2 62° = 1 - 225/289 = 64/289 =
So sin 62° = 8/17 ----(2) Hence tan 62° = sin62°/cos62° =
=
 Â

______ company is all set to acquire Danske Bank’s IT centre in India?
Essar’s Power operational 400 kV inter-state transmission line in Madhya Pradesh to Chhattisgarh for Rs 1913 crore is being purchased by which group? ...
Recently the Union Home Minister Shri Amit Shah inaugurated the 120 feet tall polo statue in which of the following states of India?
Who was the first Indian woman to win an Olympic medal?
Who has issued the guidelines on the import of gold by Tariff Rate Quota (TRQ) holders under the India-UAE Comprehensive Economic Partnership Agreement ...
Where was the 3rd EPG meeting of BIMSTEC held recently?
Which of the following Ashram is situated in Sitapur district of Uttar Pradesh?
Which of these forts is known as Gateway of Haryana?
The important centres for cricket bats and other playing goods are
Who is new CEO of Unique Identification Authority of India (UIDAI) ?