Question
when x =4 and y =-6 then find the value of 27x³ +58x²y
+31xy² +8y³?Solution
27x³ +58x²y +31xy² +8y³ =27x³ +54x²y + 4x²y +36xy²-5 xy² +8y³ =(3x+2y) ³ +4x²y -5 xy² =[3×4+2×(-6)]³ + 4×16×(-6)-5×4×36 =0-384-720 = -1104
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