Question
when x =4 and y =-6 then find the value of 27x³ +58x²y
+31xy² +8y³?Solution
27x³ +58x²y +31xy² +8y³ =27x³ +54x²y + 4x²y +36xy²-5 xy² +8y³ =(3x+2y) ³ +4x²y -5 xy² =[3×4+2×(-6)]³ + 4×16×(-6)-5×4×36 =0-384-720 = -1104
More Algebra Questions
125 ÷ 5 + 14 × 4 = ? + 72 ÷ 4 – 35
What value should come in the place of (?) in the following questions?
30% of 160 – 25% of 240 + 43 = ?
- What will come in place of the question mark (?) in the following questions?
300−40% of 200=? What will come in the place of question mark (?) in the given expression?
128 + 16 X 6 - ? = 88 + 4 X 26Â
(6 × √361) × 2.5 = ? + 125
3 √8 × √36 × 13 = ? × √169
What value should come in the place of (?) in the following questions?
√289 * 2 +3√729 * 3 + 24 ÷ 8 = ?2
?3 - 25 × 11 = 30 - 15 × 12
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
