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    5. when x =4 and y =-6 then find the value of 27x³ +58x²y +31xy² +8y³?

    Question

    when x =4 and y =-6 then find the value of 27x³ +58x²y

    +31xy² +8y³?
    A 1224 Correct Answer Incorrect Answer
    B 1624 Correct Answer Incorrect Answer
    C -1104 Correct Answer Incorrect Answer
    D -1324 Correct Answer Incorrect Answer

    Solution

    27x³ +58x²y +31xy² +8y³ =27x³ +54x²y + 4x²y +36xy²-5 xy² +8y³ =(3x+2y) ³ +4x²y -5 xy² =[3×4+2×(-6)]³ + 4×16×(-6)-5×4×36 =0-384-720 = -1104

    Practice Next
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