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(a + b + 2c) (a² + b² + 4c2- ab - 2bc - 2ca) As we know, = a3 + b³ + c3 – 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca) Put the value of c =2c. a³+b³ + 8c3 - 6abc = (a + b + 2c) (a² + b² + 4c2- ab - 2bc - 2ca). answer is a³+b³ + 8c3 - 6abc.
Equation 1: 2x2 - 21x + 54 = 0
Equation 2: 4y2 - 23y + 15 = 0
Difference between the roots of equation 1 is approx...
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 2y2 + 11y + 15 = 0
II. 3x2 + 4x - 4= 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 103x² - 470x + 367 = 0
Equation 2: 107y² - 504y + 397 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 2b2 + 31b + 99 = 0
II. 4a2 + 8a - 45 = 0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
