Question
What is the value of (aĀ² + bĀ²+4cĀ²- ab-2bc-2ca) (a +
b+2c):Solution
(a + b + 2c) (aĀ² + bĀ² + 4c2- ab - 2bc - 2ca) As we know, = a3 + bĀ³ + c3 ā 3abc = (a + b + c) (aĀ² + bĀ² + cĀ² - ab - bc - ca) Put the value of c =2c. aĀ³+bĀ³ + 8c3 - 6abc = (a + b + 2c) (aĀ² + bĀ² + 4c2- ab - 2bc - 2ca). answer is aĀ³+bĀ³ + 8c3 - 6abc.
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