Question
(x + 4) 2 + (y – 1) 2 + (z +
2) 2 = 0, then find the value of 2x - 3y + z.Solution
If (x + 4) 2 + (y – 1) 2 + (z + 2) 2 = 0, then (x = - 4), (y = 1), and (z = - 2).
So,
- x + 4 = 0 → x = -4
- y - 1 = 0 → y = 1
- z + 2 = 0 → z = -2
Therefore, required value:
2(-4) - 3(1) + (-2) = -8 - 3 - 2 = -13
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