Question
If p = 32 - q - r and pq + r(q + p) = 255, then find
the value of (p² + q² + r²).Solution
We have, p = 32 - q - r So, p + q + r = 32 And, pq + r(q + p) = 255 Or, pq + qr + pr = 255 Using, (p + q + r)² = p² + q² + r² + 2(pq + qr + pr) So, 32² = (p² + q² + r²) + 2 × 255 Or, 1024 = (p² + q² + r²) + 510 Or, p² + q² + r² = 1024 - 510 Or, p² + q² + r² = 514
23 45 89 155 ? 353
580 557 528 497 ? 419
(14.073)² + (32.103)² + (43.9653)² + (52.983)² + ? = (102.45)² + (98.007)²
Complete the series choosing the missing number.
110, 99, 86, ___, 54, 35.
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
What will come in place of the question mark (?) in the following series?
17, 81, 131, 169, 197, ?
226  231   466  ?  5606  28031    Â
10, 10, 15, 30, 75, ?
What will come in place of the question mark (?) in the following series?
72, 78, 90, ?, 132, 162
What will come in the place of questions (?) mark in the following questions.
1204, 1218, ? , 1267, 1302, 1344
Relevant for Exams:
