Question
If (5x + 2)3 + (x β 1)3 + 8(3x
β 7)3 = 6(5x + 2) Γ (x β 1) Γ (3x β 7), then the value of (5x + 3) isΒSolution
If a + b + c = 0, then a3 + b3 + c3 = 3abc Β Since, (5x + 2)3 + (x β 1)3 + 8(3x β 7)3 = (5x + 2)3 + (x β 1)3 + {2(3x β 7)3} = 3 Γ 2(3x β 7) Γ (x β 1) Γ (5x + 2) So, (5x + 2) + (x β 1) + 2(3x β 7) = 0 Or, 5x + 2 + x β 1 + 6x β 14 = 0 Or, 11x β 11 = 0 So, x = 1 So, 5x + 3 = 5 Γ 1 + 3 = 8
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