Question
If (x 2 = 6x – 9), then find the value of
[x³ + (x⁴/9)][5 - x³]Solution
x² = 6x - 9
⇒ x² - 6x + 9 = 0
⇒ (x - 3)² = 0
⇒ x = 3
Required value = [3³ + (3⁴/9)] × [5 - 3³]
= [27 + (81/9)] × [5 - 27]
= (27 + 9) × (-22)
= 36 × (-22) = -792
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