Question
If (x 2 = 2x – 1), then find the value of [x³
+ (x⁴/1)][1 - x³]Solution
x² = 2x - 1
⇒ x² - 2x + 1 = 0
⇒ (x - 1)² = 0
⇒ x = 1
Required value = [1³ + (1⁴/1)] × [1 - 1³]
= (1 + 1) × (0)
= 2 × 0 = 0
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