Question
Two years ago, age of X was 12 years less than 1.5 times his present age. The ratio of age of Y, 4 years ago to the age of Z, 6 years hence is 1:3. Find the age of Y, if the age of Z is 50% more than the age of
X.
Solution
Let the present age of X, Y and Z be ‘x’, ‘y’ and ‘z’ years respectively. x – 2 = 1.5 × x – 12 0.5 × x = 10 x = 10/0.5 x = 20 years So, age of z = 20 × 1.5 = 30 years Also, (y – 4)/(z + 6) = 1/3 y – 4 = (1/3) × 36 y = 12 + 4 = 16 years
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