Question
The present age of a mother is 4 times that of her
daughter. After 12 years, the mother’s age will be 1 year more than twice the daughter’s age. Find the present age of the daughter.Solution
Let the present age of the daughter be x years, and the mother’s age is 4x years. After 12 years, the mother’s age will be 4x + 12, and the daughter’s age will be x + 12. Given: 4x + 12 = 2(x + 12) + 1. 4x + 12 = 2x + 24 + 1. 4x - 2x = 25 - 12. 2x = 13 x = 6.5 years.
?% of (168 ÷ 8 × 20) = 126
20% of 1500 – 75% of 200 = 125% of ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
√196 + (0.25 × 144) + 19 = ? + 72
22 * 6 + 45% of 90 + 65% of 180 = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
(25 × 12 + 30 × 8 – 22 × 10) = ?
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846
