Question
The present age of a mother is 4 times that of her daughter. After 12 years, the mother’s age will be 1 year more than twice the daughter’s age. Find the present age of the daughter.
Solution
Let the present age of the daughter be x years, and the mother’s age is 4x years. After 12 years, the mother’s age will be 4x + 12, and the daughter’s age will be x + 12. Given: 4x + 12 = 2(x + 12) + 1. 4x + 12 = 2x + 24 + 1. 4x - 2x = 25 - 12. 2x = 13 x = 6.5 years.
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