Question
Six years ago, age of X was 10 years less than 1.4 times his present age. The ratio of age of Y, 2 years ago to the age of Z, 4 years hence is 1:2. Find the age of Y, if the age of Z is 60% more than the age of
X.
Solution
Let the present age of X, Y and Z be ‘x’, ‘y’ and ‘z’ years respectively. x – 6 = 1.4 × x – 10 0.4 × x = 4 x = 4/0.4 x = 10 years So, age of z = 10 × 1.6 = 16 years Also, (y – 2)/(z + 4) = 1/2 y – 2 = (1/2) × 20 y = 10 + 2 = 12 years
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