Question
A person 'M' is 5 years younger than 'N' and also 9
years less than twice the age of 'P'. Given that the ages of 'N' and 'P' are in the ratio 7:4, determine the current age of 'M'.Solution
ATQ;
Let 'N' = 7x, and 'P' = 4x
'M' = 'N' – 5 = 7x – 5
Also, 'M' = 2('P') – 9 = 2(4x) – 9 = 8x – 9
Hence, 7x – 5 = 8x – 9
x = 4
'M' = 7(4) – 5 = 28 – 5 = 23
More Age Questions
I. x= √(20+ √(20+ √(20+ √(20…………….∞)) ) )
II. y= √(5√(5√(5√(5……….∞)) ) )
...I. x2 + 13x + 42 = 0
II. y² + 13y + 40 = 0
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. √(17x) + √51 = 0
II. √(4y) + 3 = 0
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 6x² - 24x + 18 = 0
Equation 2: 5y² - 20y + 15 = 0
I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
