Question
If present age of ‘A’ is twice the age of ‘B’,
5 years ago from now and sum of their ages 4 years hence from now will be 46 years, then find the present age of ‘B’.Solution
Let present age of ‘B’ = ‘x’ years So, present age of ‘A’ = 2 × (x – 5) years ATQ, (x + 4) + {2(x – 5) + 4} = 46 Or, 3x – 2 = 46 Or, 3x = 48 Or, x = 16 So, present age of ‘B’ = 16 years
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