Question
If present age of βAβ is three times the age of
βBβ, 2 years ago from now and sum of their ages 6 years hence from now will be 54 years, then find the present age of βBβ.Solution
Let present age of βBβ = βxβ years So, present age of βAβ = 3 Γ (x β 2) years ATQ, (x + 6) + {3(x β 2) + 6} = 54 Or, 4x + 6 = 54 Or, 4x = 48 Or, x = 12 So, present age of βBβ = 12 years
8, 20, 48, 108, 232, 482
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