Question
Let the present ages of 'K' and 'L' be 'm' years and 'n'
years respectively. Four years ago, the combined age of both was 32 years. If average of 'm' and 33 is 5 more than average of 'n' and 33, what will be the age of 'K' three years later?Solution
ATQ,
m + n = 32 + 4 + 4 Or, m + n = 40 ------ (I) (m + 33) ÷ 2 = (n + 33) ÷ 2 + 5 Or, m + 33 = n + 33 + 10 Or, m = n + 10 On putting value of 'm' in equation I, We get, n + 10 + n = 40 Or, 2n = 30 Or, n = 15 On putting value of 'n' in equation I, We get, m = 15 + 10 = 25 Therefore, required age = 25 + 3 = 28 years
Simplify the following expression and find the final value:
(18 ÷ 6 of 2 + 7 of 5) ÷ 5
(1520 - 1350) ÷ (550 – 500) = ?
Simplify the following expressions and choose the correct option.
[540 ÷ (6 × 3) + 7.5 × 4] ÷ 3 = ?
(64/25)? × (125/512)?-1 = 5/8
52% of 400 + √(?) = 60% of 600 - 25% of 400
What will come in the place of question mark (?) in the given expression?
(72 × 4 – 92) ÷ 14 = ?
32% of 450 + 60% of 150 = ? × 9
82.3 × 644.7 × 723.4 × 815.85 = 72?
961 × 4 ÷ 31 – 15% of 180 = ? – 73
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