Question
Let the present ages of 'K' and 'L' be 'm' years and 'n'
years respectively. Four years ago, the combined age of both was 32 years. If average of 'm' and 33 is 5 more than average of 'n' and 33, what will be the age of 'K' three years later?Solution
ATQ,
m + n = 32 + 4 + 4 Or, m + n = 40 ------ (I) (m + 33) ÷ 2 = (n + 33) ÷ 2 + 5 Or, m + 33 = n + 33 + 10 Or, m = n + 10 On putting value of 'm' in equation I, We get, n + 10 + n = 40 Or, 2n = 30 Or, n = 15 On putting value of 'n' in equation I, We get, m = 15 + 10 = 25 Therefore, required age = 25 + 3 = 28 years
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