Question
Present age of a Father is three times more than the age
of his son. If six years ago, their ages were in ratio 7:1, respectively, then find the present age of the Father.Solution
Let the present age of son be 'x' years. So, present age of Father = x * 4 = '4x' years ATQ; {(4x - 6)/(x - 6)} = (7/1) Or, 4x - 6 = 7 * (x - 6) Or, 4x - 6 = 7x - 42 Or, 36 = 3x So, x = 12 So, present age of Father = 4 * 12 = 48 years
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