Question
The present ages of βRβ and βSβ are in the ratio
2:3. Five years later, the ratio of their ages will be 3:4. What was the age of βRβ 6 years ago?Solution
ATQ,
Let present ages of R and S be 2x and 3x years.
ATQ:
(2x + 5)/(3x + 5) = 3/4
β 4(2x + 5) = 3(3x + 5)
β 8x + 20 = 9x + 15
β x = 5
So, present age of R = 2x = 10 years
Therefore, age of R 6 years ago = 10 β 6 = 4 years
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