Question
A father is three times as old as his son. After 10
years, the father will be twice as old as the son. What is the son's present age?Solution
ATQ, Let son's present age = x Father's present age = 3x After 10 years: Son = x + 10 Father = 3x + 10 Given: 3x + 10 = 2(x + 10) 3x + 10 = 2x + 20 3x - 2x = 20 - 10 x = 10
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