Question
Present age of βRβ is 75% more than that of βSβ.
5 years ago, βRβ was 2.5 times as old as βSβ. What is the present age of βSβ?Solution
Let the present age of βSβ be βxβ years
Therefore, present age of βRβ = 1.75x years
ATQ;
(1.75x β 5) = 2.5 Γ (x β 5)
Or, 1.75x β 5 = 2.5x β 12.5
Or, 7.5 = 0.75x
Or, x = 10
Therefore, present age of βSβ = 10 years
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