Question
Present ages of P and Q are in the ratio 4:7
respectively. If Q’s age, 15 years hence from now will be 6 times of P’s age, 6 years ago from now, then find the present age of Q.Solution
Let the present ages of P and Q be 4x and 7x years respectively. According to the question, => (7x + 15) = 6 × (4x – 6) => 7x + 15 = 24x – 36 => 17x = 51 => x = 3 Therefore, the present age of Q = 7x = 21 years
2, 9, 19, 32, 48, 67, ?
64Â Â Â 48Â Â Â 36Â Â Â 22Â Â Â Â 16Â Â Â Â 8
?     190      210      238      274     318
...40 41 86 ? 1084 5445
...148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
31   48    67    90   ?      150
22, 23, 31, 57, 122, 247
1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
6Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â 40Â Â Â Â Â Â Â Â Â Â Â 32Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 249Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 240
203, 223, 198, 218, ?, 213
