Question
Age of ‘A’ after 16 years will be three time of his
age 12 years ago. Eight years hence from now, ratio of ages of ‘A’ and ‘B’ will be 2:3, respectively. If present average age of ‘A’, ‘B’ and ‘C’ is 25 years, then find the present age of ‘C’.Solution
Let A’s present age = a After 16 years: a + 16 12 years ago: a − 12 Equation 1: a + 16 = 3(a − 12) → a = 26 Let B’s present age = b After 8 years: A = 34, B = b + 8 Equation 2: 34 / (b + 8) = 2 / 3 → 102 = 2b + 16 → b = 43 Average age of A, B, C = 25 Equation 3: (26 + 43 + c) / 3 = 25 → 69 + c = 75 → c = 6 Present ages: A = 26 years B = 43 years C = 6 years
Consider two concentric circles having radii 17 cm and 15 cm. What is the length (in cm) of the chord, of the bigger circle, which is a tangent to the s...
If O is the orthocentre of ΔABC , if ∠ BOC = 105 0 then what is the measure of ∠ BAC?
In the given figure CD is parallel to AB then ∠y is?
If O is circumcentre of acute angled triangle ABC, if ∠ OBC = 150 then ∠BAC = ?
- Length of a chord in a circle of radius 'r' cm, is 40 cm and distance between chord and centre of the circle is 21 cm. Find the value of (2r + 1).
The sides of a triangle are 10 cm, 17 cm, and 21 cm. Find the area of the triangle using Heron’s formula.
The radius of the incircle of a triangle is 8 cm. if the area of the triangle is 56 cm 2 , then its perimeter is?
The internal bisector of ∆ABC at ∠A cuts BC on D and cuts the circumcircle at E. If DE = 6cm, AC = 8cm and AD = 10 cm, then find the length of AB?
Find the area of triangle having sides 5 m, 6 m, and 9 m.
Relevant for Exams:
