Question
Age of ‘A’ after 16 years will be three time of his
age 12 years ago. Eight years hence from now, ratio of ages of ‘A’ and ‘B’ will be 2:3, respectively. If present average age of ‘A’, ‘B’ and ‘C’ is 25 years, then find the present age of ‘C’.Solution
Let A’s present age = a After 16 years: a + 16 12 years ago: a − 12 Equation 1: a + 16 = 3(a − 12) → a = 26 Let B’s present age = b After 8 years: A = 34, B = b + 8 Equation 2: 34 / (b + 8) = 2 / 3 → 102 = 2b + 16 → b = 43 Average age of A, B, C = 25 Equation 3: (26 + 43 + c) / 3 = 25 → 69 + c = 75 → c = 6 Present ages: A = 26 years B = 43 years C = 6 years
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