Question
Age of βAβ after 16 years will be three time of his
age 12 years ago. Eight years hence from now, ratio of ages of βAβ and βBβ will be 2:3, respectively. If present average age of βAβ, βBβ and βCβ is 25 years, then find the present age of βCβ.Solution
Let Aβs present age = a After 16 years: a + 16 12 years ago: a β 12 Equation 1: a + 16 = 3(a β 12) β a = 26 Let Bβs present age = b After 8 years: A = 34, B = b + 8 Equation 2: 34 / (b + 8) = 2 / 3 β 102 = 2b + 16 β b = 43 Average age of A, B, C = 25 Equation 3: (26 + 43 + c) / 3 = 25 β 69 + c = 75 β c = 6 Present ages: A = 26 years B = 43 years C = 6 years
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