Question
Five years back, the age ratio of Meera and Sanya was
11:13. Five years from now, the ratio becomes 13:15. What is the average of their present ages?Solution
ATQ,
Let present age of Meera and Sanya be P years and Q years respectively.
According to question,
(P – 5)/(Q – 5) = 11/13
3P – 65 = 11Q – 55
13P – 11Q = 10 ………………….(1)
And, (P + 5)/(Q + 5) = 13/15
15P + 75 = 13Q + 65
13Q – 15P = 10 …………………..(2)
Solving equation (1) and (2), we get
P = 55 and Q = 65
Average present age of Meera and Sanya = (55 + 65)/2 = 120/2 = 60 years
- Find the simplified value of the expression:sin 2 45 o + sin 2 60 o - (1/3) X tan 2 60 o
If (cos A - sin A) = √2 cos (90° - A), then find the value of cot A.
If cos 2x = 1/2, then the value of x:
ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of ...

From a point 50 meters away from the base of a tower, the angle of elevation of the top of the tower is 30°. Find the height of the tower.
- If sin (4A − B) = (√2/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.
If 17sin A = 8, where 0