Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 10 years hence from now will be 5 times of A's age, 14 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 10) = 5 x (3x - 14) Or, 5x + 10 = 15x - 70 Or, 10x = 80 x = 8 So, present age of 'A' = 3 x 8 = 24 years
A-5,  A,  35,  52, 78, 115
30, 42, 48, 54, 65, 81, 126
- Find the wrong number in the given number series.
25, 34, 18, 34, 9, 46 Find the wrong number in the given number series.
32, 48, 72, 108, 162, 245
Find the wrong number in the given number series.
1600, 800, 1200, 400, 100 , 12.5
547, 594, 640, 691, 741, 792
Find the wrong number in the given number series.
26, 38, 60, 110, 206, 398
75, 450, 225, 1330, 675, 4050
Find the wrong number in the given number series.
8, 12, 23, 40, 66, 103
62, 79, 98, 119, 142, 165