Question
Present ages of 'A' and 'B' are in the ratio 3:5, respectively. If B's age, 14 years hence from now will be 2 times of A's age, 8 years ago from now, then find the present age of 'A'.
Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 14) = 2 x (3x - 8) Or, 5x + 14 = 6x - 16 Or, x = 30 So, present age of 'A' = 3 x 30 = 90 years
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