Question
Present age of βAβ is 25% more than that of βBβ.
If 16 years hence from now, βBβ will be 9 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.25 = β1.25xβ years ATQ; (x + 16) + 9 = (1.25x + 16) Or, x + 25 = 1.25x + 16 Or, 9 = 0.25x Or, x = 36 So, present age of βBβ = 36 years And, present age of βAβ = 36 + 9 = 45 years Required sum = 36 + 45 = 81 years
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