A bag contains 7 (one rupee coins), 4 (two rupee coin) and 5 (ten rupee coin). Find the probability that 3 coins drawn at random are either (two rupee coins) or (ten rupee coins)?
ATQ, we can say that, Total number of coins are = 7 + 4 + 5 = 16 Therefore P(E) = n(E)/n(S) Required probability = ( 4C3 + 5C3 )/ (16C3 ) = (4 + 10)/560 = 14/560 = 1/40
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