Question
18 rotten bananas are accidentally mixed with 132 good
ones. It is not possible to just look at a banana and tell whether or not it is rotten. One banana is taken out at random from this lot. Determine the probability that the banana is taken out is a good one.Solution
Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 132 + 18 = 150 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 132/150 = 22/25
More Probability Questions
2(3/4) of 2880 + 54% of 7520 - ? = 302
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
- What will come in place of (?), in the given expression.
(5³ + 3²) × 2 = ? (1225/25) - (192/96) + (50/5) = ?
What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) ÷ 15 X ? = 36 X 30
- What will come in place of (?), in the given expression.
75% of 640 – 20% of 150 = ? `(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
95% of 830 - ? % of 2770 = 650
