Question
Present age of βAβ is 40% more than that of βBβ.
If 11 years hence from now, βBβ will be 10 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 11) + 10 = (1.40x + 11) Or, x + 21 = 1.40x + 11 Or, 10 = 0.40x Or, x = 25 So, present age of βBβ = 25 years And, present age of βAβ = 25 + 10 = 35 years Required sum = 25 + 35 = 60 years
Evaluate:
β729 + β49 - β16 + 1/β64
Simplify:

(1/5)(40% of 800 β 120) = ? Γ 5
2/5 of 3/4 of 7/9 of 7200 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
? = (22% of 25% of 60% of 3000) + 21
Determine the simplified value of the given mathematical expression.
(342 β 20% of 5280) = ? Γ· 3
β157464 =?