Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 10 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 10 = (1.40x + 11) Or, x + 21 = 1.40x + 11 Or, 10 = 0.40x Or, x = 25 So, present age of ‘B’ = 25 years And, present age of ‘A’ = 25 + 10 = 35 years Required sum = 25 + 35 = 60 years
Find the missing number in the given number series.
4, 9, 20, 37, 60, ?Complete the series choosing the missing number.
110, 99, 86, ___, 54, 35.
18, 21, 45, 138, 555, ?
728, 737, ?, 778, 814, 863Â
23Â Â Â Â 44Â Â Â Â 64Â Â Â Â 83Â Â Â Â Â ? Â Â Â Â Â 118
...5 6 15 40 89 170 ?
...12, 16, ?, 48, 76, 112
What will come in the place of questions (?) mark in the following questions.
1279, 1265, ? , 1225, 1193, 1149
84, 63, ?, 283.5, 1701
Choose the missing term?
B, D, F, I, L, P, ?
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