Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 10 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 10 = (1.40x + 11) Or, x + 21 = 1.40x + 11 Or, 10 = 0.40x Or, x = 25 So, present age of ‘B’ = 25 years And, present age of ‘A’ = 25 + 10 = 35 years Required sum = 25 + 35 = 60 years
7, 9, 21, ?, 107, 197
What will come in place of the question mark (?) in the following series?
112, 124, 138, 154, ?, 196
9 28 83 250 ? 2248
18Â Â Â 19Â Â Â 34Â Â Â 111Â Â Â Â 428Â Â Â Â 2165Â Â Â Â ?
...What will come in place of the question mark (?) in the following series?
17, 138, 307, 532, ?, 1182
5Â Â Â Â 12Â Â Â Â 26Â Â Â Â 47Â Â Â Â Â ? Â Â Â Â Â Â 110
...What will come in place of the question mark (?) in the following series?
144, ?, 154, 114, 194, 34
- What will come in place of (?) in the given number series.
7, 14, 28, 56, ?, 224 4, 9, 25, ?, 121, 169
What will come in place of the question mark (?) in the following series?
?, 65, 37, 73, 29, 81
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