Question
In a school there are 20 girls. The average age of the
girls is decreased by 2 months when one girl aged 18 years is 8 replaced by a new girl. What is the age of the new girl?Solution
Let the sum of age of 19 girls be x years and the Age of the new girls be y years. Old Average = (Sum of the age of 19 girls + Age of the girl to be replaced)/Total number of girls => (x + 18) / 20 New Average = (Sum of the age of 19 girls + Age of the new girl) / 20 According to the question, As we know The average age of the girls is decreased by 2 months when one girl aged 18 years is replaced i.e. Old Averag - New Average = 2 month ⇒ {(x + 18)/20} – {(x + y)/20} = (2/12) ⇒ 18 – y = 10/3 ⇒ y = 44/3 years ⇒ y = 14 years 8 months ∴ The age of new girl is 14 years 8 months.
Simplify (cos13°+sin 13°) /(cos13°-sin13°)
If sec A + tan A = (9/4) and sec A - tan A = (4/9), find the value of cos A.
If tan θ + cot θ = 2 where 0 < θ < 90 ; find the value of tan17 θ + cot19 θ.
tan 20Ëš x tan 23Ëš x tan 67Ëš x tan 70Ëš = ?
Find the value of the following:sin(36° + A) × cos(54° – A) + cos(36° + A) × sin(54°–A)
- In a triangle ABC, if 5∠A = 3∠B = 15∠C, then find the value of cosA + sin(C + 10 ° )

- From the top of a tower, the angle of depression to the top of a man's head is 60°. The man is 4 feet tall and is standing 20 feet away from the base of t...
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...if cot x- tan x=7 then what is the value of cot x + tan x=?