Question
15 years ago, A was 1/5 of B’s age. If the ratio
of their present ages is 3:5, what will be the sum of their present ages?Solution
Let the present age of A and B be 3x and 5x respectively. According to question, => 5(3x – 15) = (5x – 15) => 15x – 75 = 5x – 15 => 10x = 60 => x = 6 Present age of A = 3x = 18 yrs And present age of B = 5x = 30 yrs The sum of their present ages = 18 + 30 = 48 years
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8