Question
Find the smallest value of 'x' ('x' is a natural number)
such that '47x821' is completely divisible by 3.Solution
A number is divisible by 3 when sum of its digits is divisible by 3.
Sum of digits = 4 + 7 + x + 8 + 2 + 1 = (x + 22)
(x + 22) is divisible by 3 when 'x' = 2, 5 or 8
Since we need the smallest natural number, 'x' = 2
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