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Some tyres are rains (I) + No rains is a flower (E) ⇒ Some tyres are not flowers (O) ⇒ [Probable conclusion] ⇒ Some tyres may be flowers (I). No rain is a flowers (E) + All flowers are jungles (A) ⇒ Some jungles are not rains (O*). All flowers are jungles (A) + All jungles are petals (A) ⇒ All flowers are petals (A) ⇒ I.I. ⇒ Some flowers are petals (I). Hence, option 4 is correct. By elimination method - By 1, No + no = no. no +ve relation can be drawn between flower and petal. Hence it is eliminated. By 2, some + some = no relation can be drawn between flower and petal. Hence it is eliminated. By3, All + no = no +ve relation can be drawn between flower and petal. Hence it is eliminated. Hence answer is option 4.
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